Saturday, June 29, 2013

Print the objects of an array in the order of decreasing frequency. PS: Please make sure order of object should remain same

E.g. if array is of integer is given as  5 2 2 8 5 6 8 8, then we should get 8 8 8 5 5 2 2 6 , here freq. of 5 and 2 are same but 5 comes before 2 in array thus its should come before in output as well.

Here is the working code , let me know if it will fail for any test case and  if we can improve it?



/********************************************************
Time Complexity : O(n)+O(nlogn)+O(n)=O(nlogn)
Space Complexity : Auxallery Space O(2n)= O(n)
*********************************************************/
 Run Here http://ideone.com/FQ65xM

Wednesday, May 22, 2013

Given a sequence of n real numbers A(1) ... A(n), determine a contiguous subsequence A(i) ... A(j) for which the sum of elements in the subsequence is maximized


#include<stdio.h>
#define MAX(a,b) ((a>b)?(a):(b))
main()
{
  int arr[]={-2, -3, 4, -1, -2, 1, 5, -3};
  int len,i;
  int max=0;
  len = sizeof(arr)/sizeof(arr[0]);
  max=arr[0];
  int finalmax=0;
  int start=0,end=0;
  for(i=1;i<len;i++)
  {
    max = MAX(max+arr[i], arr[i]); 
      
        finalmax=MAX(max,finalmax);
    
  }
 
    
      printf("MAX:%d %d %d \n",finalmax, start ,end);
 
   
   
}
Example if you want to print array http://codepad.org/BhYxSlp4

Tuesday, March 19, 2013

How would you design a logging system for something like Google , you should be able to query for the number of times a URL was opened within two time frames.


i/p : start_time , end_time , URL1 
o/p : number of times URL1 was opened between start and end time.
Some specs : Database is not an optimal solution A URL might have been opened multiple times for given time stamp. A URL might have been opened a large number of times within two time stamps. start_time and end_time can be a month apart. time could be granular to a second.