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4 comments :
Let, r1 = current node of 1st tree r2 = current node of 2nd tree
There are some of the cases I think we need to consider:
Case 1 : r1.data < r2.data
2 subproblems to solve:
first, check r1 and r2.left
second, check r1.right and r2
Case 2 : r1.data > r2.data
2 subproblems to solve:
- first, check r1.left and r2
- second, check r1 and r2.right
Case 3 : r1.data == r2.data
Again, 2 cases to consider here:
(a) current node is part of largest common BST
compute common subtree size rooted at r1 and r2
(b)current node is NOT part of largest common BST
2 subproblems to solve:
first, solve r1.left and r2.left
second, solve r1.right and r2.right
@anon yes i had similer approach in mind but due to lake of time wasen't able to put solution will look at code & then post itf will cover all the test cases
Shashank :)
Without explanation why u post these type of questions? There lot of sites to do that,what is the use from your site? Here i see lot of questions are time inefficient and most of them are not solved
@Anon...Is its ur frustration or comment that u didn't get working code for this question ...but if u look at 450 problems out of 500+ u will each has efficient & working solution :) never mind , i will post soln of this as well ..but let me know how efficient u can think for this question ??
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